Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.1 Vectors in the Plane - 11.1 Exercises - Page 769: 64

Answer

$x=\left(-3,2\right)$

Work Step by Step

We are given: $x=(a,b)$ $u=(2,-3)$ $v=(-4,1)$ $2x+u=v$ Substitute the expressions of the vectors in the equation: $2(a,b)+(2,-3)=(-4,1)$ $(2a,2b)+(2,-3)=(-4,1)$ $(2a+2,2b-3)=(-4,1)$ Determine $a,b$: $\begin{cases} 2a+2=-4\\ 2b-3=1 \end{cases}$ $\begin{cases} 2a=-4-2\\ 2b=1+3 \end{cases}$ $\begin{cases} 2a=-6\\ 2b=4 \end{cases}$ $a=\dfrac{-6}{2}=-3$ $b=\dfrac{4}{2}=2$ The solution is: $x=\left(-3,2\right)$
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