## Calculus: Early Transcendentals (2nd Edition)

$x=\dfrac{4}{3}+\dfrac{\log15}{3\log3}\approx2.15$
$3^{3x-4}=15$ Apply $\log$ to both sides of the equation: $\log3^{3x-4}=\log15$ Take the exponent on the left side of the equation down to multiply in front of its respective $\log$: $(3x-4)\log3=\log15$ Take $\log3$ to divide the right side: $3x-4=\dfrac{\log15}{\log3}$ Take $4$ to the right side: $3x=4+\dfrac{\log15}{\log3}$ Take $3$ to divide the right side: $x=\dfrac{4}{3}+\dfrac{\log15}{3\log3}\approx2.15$