Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.3 Inverse, Exponential, and Logarithmic Functions - 1.3 Exercises - Page 36: 26


$f^{-1}(x)=\sqrt (y-4)$

Work Step by Step

$f(x)=x^{2}+4$ $y=x^{2}+4$ $y-4=x^{2}$ $\sqrt (y-4)=x$ $f^{-1}(x)=\sqrt (y-4)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.