Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.3 Inverse, Exponential, and Logarithmic Functions - 1.3 Exercises - Page 36: 26

Answer

$f^{-1}(x)=\sqrt (y-4)$

Work Step by Step

$f(x)=x^{2}+4$ $y=x^{2}+4$ $y-4=x^{2}$ $\sqrt (y-4)=x$ $f^{-1}(x)=\sqrt (y-4)$
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