## Calculus: Early Transcendentals (2nd Edition)

$f(x)=8-4x$ $f^{-1}(x)=\dfrac{8-x}{4}$
$f(x)=8-4x$ Substitute $f(x)$ by $y$: $y=8-4x$ Solve the equation for $x$. Start by taking $4x$ to the left side and $y$ to the right side: $4x=8-y$ Take $4$ to divide the right side: $x=\dfrac{8-y}{4}$ Interchange $x$ and $y$: $y=\dfrac{8-x}{4}$ Substitute $y$ by $f^{-1}(x)$: $f^{-1}(x)=\dfrac{8-x}{4}$ The graph of both the function and its inverse is shown in the answer section.