## Calculus: Early Transcendentals (2nd Edition)

$f(x)=4x-12$ $f^{-1}(x)=\dfrac{x+12}{4}$
$f(x)=4x-12$ Substitute $f(x)$ by $y$: $y=4x-12$ Solve the equation for $x$. Do so by taking $12$ to the left side and rearranging the equation: $y+12=4x$ $4x=y+12$ Take $4$ to divide the right side: $x=\dfrac{y+12}{4}$ Interchange $x$ and $y$: $y=\dfrac{x+12}{4}$ Substitute $y$ by $f^{-1}(x)$: $f^{-1}(x)=\dfrac{x+12}{4}$ The graph of both the original function and its inverse is shown in the answer section.