Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.3* The Natural Exponential Function - 6.3* Exercises - Page 453: 52



Work Step by Step

$f'(t)=\frac{d}{dt}sin^{2}(e^{sin^{2}t})$ $=2sin(e^{sin^{2}t})\frac{d}{dt}[sin(e^{sin^{2}t})]$ $=2sin(e^{sin^{2}t})cos(e^{sin^{2}t}).(e^{sin^{2}t})\frac{d}{dt}({sin^{2}t)}$ $=sin2(e^{sin^{2}t})(e^{sin^{2}t})(2sintcost)$ Hence,$f'(t)=sin2t(e^{sin^{2}t})[sin(2e^{sin^{2}t})]$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.