Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.3* The Natural Exponential Function - 6.3* Exercises - Page 453: 35



Work Step by Step

$\frac{d}{dx}(3x^2-5x)e^x$ $=(3x^2-5x)\frac{d}{dx}e^x+e^x\frac{d}{dx}(3x^2-5x)$ $=(3x^2-5x)e^x+e^x(6x-5)$ $=(3x^2-5x+6x-5)e^x$ $=(3x^2+x-5)e^x$
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