Answer
$\frac{10x+1}{5x^2+x-2}$
Work Step by Step
$\frac{d}{dx}\ln|2-x-5x^2|$
$=\frac{1}{2-x-5x^2}\frac{d}{dx}(2-x-5x^2)$
$=\frac{1}{2-x-5x^2}*(-1-10x)$
$=\frac{-1-10x}{2-x-5x^2}$
$=\frac{-1-10x}{2-x-5x^2}*\frac{-1}{-1}$
$=\frac{10x+1}{5x^2+x-2}$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 6 - Inverse Functions - 6.2* The Natural Logarithmic Functions - 6.2* Exercises - Page 446: 33
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