Answer
$2\cot x$
Work Step by Step
$\frac{d}{dx}\ln(\sin^2x)$
$=\frac{1}{\sin^2x}*\frac{d}{dx}\sin^2x$
$=\frac{1}{\sin^2x}*2\sin x *\frac{d}{dx}\sin x$
$=\frac{1}{\sin^2x}*2\sin x *\cos x$
$=\frac{2\cos x}{\sin x}$
$=2\cot x$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 6 - Inverse Functions - 6.2* The Natural Logarithmic Functions - 6.2* Exercises - Page 446: 20
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