Answer
$\frac{\sin x}{x}+\cos x\ln(5x)$
Work Step by Step
$\frac{d}{dx}\sin x\ln(5x)$
$=\sin x\frac{d}{dx}\ln(5x)+\ln(5x)\frac{d}{dx}\sin x$
$=\sin x\frac{1}{5x}\frac{d}{dx}(5x)+\ln(5x)\cos x$
$=\sin x\frac{1}{5x}*5+\cos x\ln(5x)$
$=\frac{\sin x}{x}+\cos x\ln(5x)$
