## Calculus 8th Edition

$4x+y+2z=2$
Mid point of points $(2,5,5)$ and $(-6,3,1)$ is $M=(-2,4,3)$ Normal vector: $n=\lt -8,-2,-4\gt$ Plug these points and the vector components of the normal vector in the equation of the plane. Thus, $-8(x+2)-2( y-4)-4(z-3)=0$ $-8x-16-2y+8-4z+12=0$ $8x+2y+4z=4$ Hence, the equation of plane is: $4x+y+2z=2$