Answer
See the attached image.
Work Step by Step
Given: $6x-3y+4z=6$
$x$-intercept $6x=6$ $\implies$ $x=1$
$y$-intercept $-3y=6$ $\implies$ $y=-2$
$z$-intercept $4z=6$ $\implies$ $z=\frac{3}{2}$
The graph is depicted as below:
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 12 - Vectors and the Geometry of Space - 12.5 Equations of Lines and Planes - 12.5 Exercises - Page 872: 43
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