Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 12 - Vectors and the Geometry of Space - 12.5 Equations of Lines and Planes - 12.5 Exercises - Page 872: 43

Answer

See the attached image.

Work Step by Step

Given: $6x-3y+4z=6$ $x$-intercept $6x=6$ $\implies$ $x=1$ $y$-intercept $-3y=6$ $\implies$ $y=-2$ $z$-intercept $4z=6$ $\implies$ $z=\frac{3}{2}$ The graph is depicted as below:
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