Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 12 - Vectors and the Geometry of Space - 12.5 Equations of Lines and Planes - 12.5 Exercises - Page 872: 49

Answer

$\lt 1,0,-1\gt$

Work Step by Step

Given: Line of intersections of the planes $x+y+z=1$ and $x+z=0$ $n_1=\lt 1,1,1\gt$ and $n_2=\lt 1,0,1\gt$ Take the cross product of the two normal vectors. $n_1 \times n_2=\lt 1,1,1\gt \times \lt 1,0,1\gt$ $=\lt 1,0,-1\gt$
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