## Calculus 8th Edition

$x+2y+z=5$
Mid point of points $(3,4,0)$ and $(1,0,-2)$ is $M=(2,2,-1)$ Normal vector: $n=\lt 1,2,1\gt$ Transform $M$ into vector form as: $M=\lt x-2, y-2,z+1\gt$ $n \cdot M= \lt 1,2,1\gt \cdot \lt x-2, y-2,z+1\gt =0$ $1(x-2)+2( y-2)+1(z+1)=0$ Hence, the equation of plane is: $x+2y+z=5$