Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 12 - Vectors and the Geometry of Space - 12.2 Vectors - 12.2 Exercises - Page 845: 28

Answer

As a result $\theta=36.87^\circ$.

Work Step by Step

We are give the vector $\langle 8,6\rangle$. In order to find the angle between the vector and the x-axis we can turn the vector into a right triangle and then apply trigonometry in order to solve for the angle. $\tan{\theta}=\frac{6}{8}\Rightarrow\theta=\arctan{\frac{6}{8}}=36.87^\circ$
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