Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 12 - Vectors and the Geometry of Space - 12.2 Vectors - 12.2 Exercises - Page 845: 25

Answer

As a result we get $\frac{1}{9}\langle8,-1,4\rangle$.

Work Step by Step

We are given $\langle8,-1,4\rangle$. In order to make this a unit vector we need to scale this vector by $\frac{1}{|\langle8,-1,4\rangle|}$. $|\langle8,-1,4\rangle|=\sqrt{(8)^2+(-1)^2+(4)^2}=\sqrt{81}\Rightarrow\frac{1}{9}\langle8,-1,4\rangle$
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