Answer
$\overrightarrow{v}=<\frac{3}{\sqrt {10}},\frac{-1}{\sqrt {10}}>$
Work Step by Step
To find the unit vector $\overrightarrow{v}$ we simply divide the original vector $\overrightarrow{a}$ by its own magnitude, $|\overrightarrow{a}|$.
$\overrightarrow{a}=<6,-2>$
$|\overrightarrow{a}|= \sqrt{6^2+(-2)^2}=2\sqrt {10}$
$\overrightarrow{v}=(\frac{1}{2\sqrt {10}})<6,-2>$
$$\overrightarrow{v}=<\frac{3}{\sqrt {10}},\frac{-1}{\sqrt {10}}>$$
