Answer
As a result we get $\frac{1}{\sqrt{35}}\langle-5,3,-1\rangle$.
Work Step by Step
We are given $\langle -5,3,-1\rangle$. In order to turn this into a unit vector we must divide by a scalar that is equal to the vector magnitude.
$|\langle-5,3,-1\rangle|=\sqrt{(-5)^2+(3)^2+(-1)^2}=\sqrt{35}\Rightarrow\frac{1}{\sqrt{35}}\langle-5,3,-1\rangle$
