# Chapter 11 - Infinite Sequences and Series - 11.1 Sequences - 11.1 Exercises - Page 744: 9

$1, 2,7,32,157$

#### Work Step by Step

Given: $a_{n}=1,a_{(n+1)}=5a_{n}-3$ $a_{1}=1$ $a_{(2)}=5a_{1}-3=5(1)-3=2$ $a_{(3)}=5a_{2}-3=5(2)-3=7$ $a_{(4)}=5a_{3}-3=5(7)-3=32$ $a_{(5)}=5a_{4}-3=5(32)-3=157$ Hence we see that the first five terms are $1, 2,7,32,157$

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