Calculus 8th Edition

$1, 2,7,32,157$
Given: $a_{n}=1,a_{(n+1)}=5a_{n}-3$ $a_{1}=1$ $a_{(2)}=5a_{1}-3=5(1)-3=2$ $a_{(3)}=5a_{2}-3=5(2)-3=7$ $a_{(4)}=5a_{3}-3=5(7)-3=32$ $a_{(5)}=5a_{4}-3=5(32)-3=157$ Hence we see that the first five terms are $1, 2,7,32,157$