## Calculus 8th Edition

converges to $0$
Divide top and bottom by $9^n$. We have $\lim\limits_{n \to \infty}$ $\frac{(\frac{4}{9})^{n}}{(\frac{1}{9^{n}})+1}$ = $\frac{0}{1}$ = 0. Hence, the sequence converges to $0$.