Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 11 - Infinite Sequences and Series - 11.1 Sequences - 11.1 Exercises - Page 744: 38

Answer

converges to $1$

Work Step by Step

We can write $\ln{2n}$ as $\ln{2} + \ln{n}$. Hence $$a_n = \frac{\ln{n}}{\ln{2} + \ln{n}} = \frac{1}{\frac{\ln{2}}{\ln{n}} + 1}.$$ Since the fraction in the denominator approaches 0 as $n \to \infty$, our sequence converges to $\frac{1}{0 + 1} = 1$.
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