Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 11 - Infinite Sequences and Series - 11.1 Sequences - 11.1 Exercises - Page 744: 24



Work Step by Step

Since the highest degree of $n$ in the numerator is 2 and the highest degree in the denominator is 1, the limit as $n$ approaches infinity will resemble that of $\frac{5n^2}{n} = 5n$, which is infinite as $n \to \infty$. Hence the sequence diverges.
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