## Calculus 8th Edition

Published by Cengage

# Chapter 1 - Functions and Limits - Review - True-False Quiz: 11

TRUE

#### Work Step by Step

TRUE $\lim\limits_{x \to 3}{\frac{x^2-9}{x-3}}=\lim\limits_{x \to 3}{\frac{(x-3)(x+3)}{(x-3)}}=\lim\limits_{x \to 3}{\frac{(x+3)}{1}}=\lim\limits_{x \to 3}{(x+3)}$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.