Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - Review - True-False Quiz - Page 95: 11



Work Step by Step

TRUE $\lim\limits_{x \to 3}{\frac{x^2-9}{x-3}}=\lim\limits_{x \to 3}{\frac{(x-3)(x+3)}{(x-3)}}=\lim\limits_{x \to 3}{\frac{(x+3)}{1}}=\lim\limits_{x \to 3}{(x+3)}$
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