Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - Review - True-False Quiz: 10



Work Step by Step

$\frac{(x^2 -9)}{(x-3)} = \frac{(x+3)(x-3)}{(x-3)} = \frac{(x+3)}{1} = x+3$ When you factor out the numerator one of the factors cancels out the denominator, making the expression equal to the other factor. Thus, $\frac{(x^2 -9)}{(x-3)}= x+3$ Which makes the answer true.
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