Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - 8.1 Integration by Parts - Exercises: 8

Answer

$$\int (2x+1)e^{x}dx=(2x+1)e^{x}-2e^{x}+C$$

Work Step by Step

$${[(2x+1)e^{x}]}'=(2x+1)e^{x}+2e^{x}$$ $$\int (2x+1)e^{x}dx=(2x+1)e^{x}-2\int e^{x}dx$$ $$=(2x+1)e^{x}-2e^{x}+C$$
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