Answer
$$1$$
Work Step by Step
We have
$$
\lim _{x \rightarrow 0} \frac{\tan x}{x} =\frac{0}{0}
$$
is an intermediate form, then we can apply L’Hôpital’s Rule as follows
$$
\lim _{x \rightarrow 0} \frac{\tan x}{x} =
\lim _{x \rightarrow 0} \frac{\sec^2 x}{1} =1.
$$
