# Chapter 7 - Exponential Functions - 7.7 L'Hôpital's Rule - Exercises - Page 366: 11

$$-\frac{9}{2}$$

#### Work Step by Step

Since $$\lim _{x \rightarrow \infty} \frac{9x +4 }{3-2x}=-\frac{\infty}{\infty}$$ is an intermediate form, then we can apply L’Hôpital’s Rule as follws $$\lim _{x \rightarrow \infty} \frac{9 }{-2}=-\frac{9}{2}.$$

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