Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.7 L'Hôpital's Rule - Exercises - Page 366: 22



Work Step by Step

We have $$ \lim _{x \rightarrow \infty} \frac{3x^3+4x^2}{4x^3-7}=\frac{\infty}{\infty}. $$ is an intermediate form, then we can apply L’Hôpital’s Rule as follows $$ \lim _{x \rightarrow \infty} \frac{9x^2+8x}{12x^2}=\lim _{x \rightarrow \infty} \frac{9+8/x}{12}=\frac{9}{12}=\frac{3}{4}. $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.