Answer
$0.36 g.$
Work Step by Step
The total mass of the deposit is given by
$$
\int_{0}^{6} s(x) d x=\int_{0}^{6} 0.01 x(6-x) d x=\left.\left(0.03 x^{2}-\frac{0.01}{3} x^{3}\right)\right|_{0} ^{6}=0.36 g.
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 6 - Applications of the Integral - 6.2 Setting Up Integrals: Volume, Density, Average Value - Exercises - Page 298: 27
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