Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 5 - The Integral - 5.1 Approximating and Computing Area - Exercises - Page 236: 37



Work Step by Step

\begin{equation} \sum_{n=51}^{150}n^{2}=\sum_{n=1}^{150}n^{2}-\sum_{n=1}^{50}n^{2}\end{equation}\begin{equation}=\frac{150(150+1)(2\times150+1)}{6}-\frac{50(50+1)(2\times50+1)}{6}\end{equation}\begin{equation}=1,093,350 \end{equation}
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