Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - Chapter Review Exercises - Page 163: 43


$$ y'= -3t^{-4}\sec^2t^{-3}.$$

Work Step by Step

Since $ y=\tan t^{-3}$, the derivative $ y'$, by using the chain rule, is given by $$ y'=\sec^2 t^{-3} (-3t^{-4})=-3t^{-4}\sec^2t^{-3}.$$
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