Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - Chapter Review Exercises - Page 163: 44

Answer

$$ y'= 12\sin(2-3x).$$

Work Step by Step

Recall that $(\cos x)'=-\sin x$. Since $ y=4\cos(2-3x)$, then by the chain rule, the derivative $ y'$ is given by $$ y'=-4\sin(2-3x) (-3)=12\sin(2-3x).$$
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