Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - Chapter Review Exercises - Page 163: 30


$$ y'= 8x+2x^{-3}.$$

Work Step by Step

Recall that $(x^n)'=nx^{n-1}$ Since $ y=4x^2-x^{-2}$, then the derivative $ y'$ is given by $$ y'= 4(2)x- (-2)x^{-2-1}=8x+2x^{-3}.$$
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