Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - Chapter Review Exercises - Page 163: 27


$$ y'=15 x^4-14x.$$

Work Step by Step

Recall that $(x^n)'=nx^{n-1}$ Since $ y=3x^5-7x^2+4$, then the derivative $ y'$ is given by $$ y'=3\times5x^{5-1}-2\times7x^{2-1}+0$$ $$=15 x^4-14x$$
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