Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.7 The Chain Rule - Exercises - Page 146: 38



Work Step by Step

Using the chain rule, we have $\frac{d}{d\theta}(\tan(\theta^{2}-4\theta))$ $=\sec^{2}(\theta^{2}-4\theta)\times\frac{d}{d\theta}(\theta^{2}-4\theta)$ That is, we take the derivative of the main function$\times$derivative of the inner function. $=\sec^{2}(\theta^{2}-4\theta)\times(2\theta-4)$
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