Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.7 The Chain Rule - Exercises: 29

Answer

y'=2xcos($x^{2}$)

Work Step by Step

The chain rule states that if y=g(h(x)), then y'=g'(h(x))h'(x). Since y=sin($x^{2}$), we can set g(x)=sin(x) (outside function) and h(x)=$x^{2}$ (inside function), and use the chain rule to find y'. Therefore, y'=g'($x^{2}$)h'(x) We know that $\frac{d}{dx}$[sin(x)]=cos(x), it'd be a good idea to memorize this derivative $\frac{d}{dx}$[$x^{2}$]=2x, using the power rule Now that we know that g'(x)=cos(x) and h'(x)=2x, we can find y'. y'=cos($x^{2}$)*(2x) =2xcos($x^{2}$)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.