Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.7 The Chain Rule - Exercises - Page 146: 24

Answer

$f'(g(x)) = 2cosx$

Work Step by Step

$f(u) = 2u + 1, g(x) = 2x+1$ $f(g(x)) = 2(sinx) + 1$ $f'(g(x)) = 2cosx + 0$ $f'(g(x)) = 2cosx$
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