#### Answer

$f'(x) = -(10+30x)(4-2x-3x^2)^4$

#### Work Step by Step

In order to derivate this function you have to apply the chain rule
Let's make an «u» substitution to make it easier
$u = 4-2x-3x^2$
$f(u) = u^5$
Derivate the function:
$f'(u) = 5u^4u'$
Now let's find u'
$u' = -2-6x$
Then undo the substitution, simplify and get the answer:
$f'(x) = 5( (-2-6x)$
$f'(x) = -(10+30x)(4-2x-3x^2)^4$