#### Answer

$y' = 16x^{-1/5} -4x^{-1/3} $
$y'' = \dfrac{4}{3}x^{-4/3}-\dfrac{16}{5}x^{-6/5}$
$y''' = \dfrac{96}{25}x^{-11/5}-\dfrac{16}{9}x^{-7/3}$

Published by
W. H. Freeman

ISBN 10:
1464125260

ISBN 13:
978-1-46412-526-3

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