Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.5 Higher Derivatives - Exercises - Page 135: 23



Work Step by Step

Since $ f(x)=\frac{12}{x}-x^3$, then we get $$ f'(x)=-\frac{12}{x^2}-3x^2, \quad f''(x)=\frac{24}{x^3}-6x, \quad f'''(x)=-\frac{72}{x^4}-6.$$ Hence, $ f'''(-3)=-\frac{72}{81}-6=-\frac{558}{81}$.
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