Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 3 - Differentiation - 3.5 Higher Derivatives - Exercises - Page 135: 8

Answer

$y' = -\dfrac{9}{5}x^{-14/5}$ $y'' = \dfrac{126}{25}x^{-19/5}$ $y''' = -\dfrac{2394}{125}x^{-24/5}$

Work Step by Step

$y' = -\dfrac{9}{5}x^{-14/5}$ $y'' = \dfrac{126}{25}x^{-19/5}$ $y''' = -\dfrac{2394}{125}x^{-24/5}$
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