Answer
$y' = \dfrac{1}{2\sqrt{x}}$
$y'' = -\dfrac{1}{4\sqrt {x^3}}$
$y''' = \dfrac{3}{8\sqrt {x^5}}$
Work Step by Step
$y' = \dfrac{1}{2\sqrt{x}}$
$y'' = -\dfrac{1}{4\sqrt {x^3}}$
$y''' = \dfrac{3}{8\sqrt {x^5}}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.5 Higher Derivatives - Exercises - Page 135: 6
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
