Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.2 Limits: A Numerical and Graphical Approach - Exercises - Page 54: 26



Work Step by Step

We have $$ \lim _{x \rightarrow 1^-} \frac{3-x}{x-1}= -\infty. $$ We know that the limit from the left will be negative infinity because the numerator will be positive (since 3 is greater than 1), while the denominator will be negative and arbitrarily close to zero.
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