Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.2 Limits: A Numerical and Graphical Approach - Exercises - Page 54: 14


See the proof below.

Work Step by Step

We have $$ |3x^2-9-(-9)| =|3x^2-9+9| = |3x^2-0| =3x|x-0|$$ Because $|3x^2-9 -(9)| $ is a multiple of $|x-0|$, then $|3x^2-9 -(9)| $ is arbitrarily small whenever $ x $ is sufficiently close to $0$. Hence, we get $$\lim_{x\rightarrow 0}3x^2-9=-9.$$
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