## Calculus (3rd Edition)

Evaluating the function at -4, it is of the form 0/0. We try to cancel the factors and rewrite the function. $\lim\limits_{x \to -4}\frac{2x^{2}-32}{x+4}$= $\lim\limits_{x \to -4}\frac{2(x+4)(x-4)}{x+4}$= $\lim\limits_{x \to -4}2(x-4)$ = 2(-4-4)= 2(-8) = -16