Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.2 Limits: A Numerical and Graphical Approach - Exercises - Page 54: 11

Answer

See the proof below.

Work Step by Step

We have $$ |5x+2-17| = |5x-15| =5|x-3|$$ Since $|5x+2− 17| $ is a multiple of $|x-3|$, then $|5x+2− 17| $ is small whenever $ x $ is sufficiently close to $3 $. Hence, we get $$ \lim _{x \rightarrow 3} 5x+2 =17.$$
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