#### Answer

$$ f(x,y)=x^2y+C$$

#### Work Step by Step

Take $$ f(x,y)=x^2y+C.$$
Taking the partial derivatives, we get the desired result:
$$ f_x=2xy, \quad f_y =x^2.$$

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Published by
W. H. Freeman

ISBN 10:
1464125260

ISBN 13:
978-1-46412-526-3

$$ f(x,y)=x^2y+C$$

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