#### Answer

$ f_{xv}=0$

#### Work Step by Step

We first differentiate with respect to $ x $; then we have
$$ f_x=\frac{2x}{3y^2+\ln(2+u^2)}.$$
Then, we compute $ f_{xv}$, which gives directly
$$ f_{xv}=0.$$
Now, we have
$$ f_{uvxyvu}=0.$$

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Published by
W. H. Freeman

ISBN 10:
1464125260

ISBN 13:
978-1-46412-526-3

$ f_{xv}=0$

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