Answer
$$
W_r= e^{r+s}, \quad
W_s= e^{r+s} .
$$
Work Step by Step
Recall that $(e^x)'=e^x$
Since $ W=e^{r+s}$, then by using the chain rule, we have
$$
W_r= e^{r+s} (1)=e^{r+s}, \quad
W_s= e^{r+s}(1)=e^{r+s} .
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 15 - Differentiation in Several Variables - 15.3 Partial Derivatives - Exercises - Page 781: 27
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