Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 15 - Differentiation in Several Variables - 15.3 Partial Derivatives - Exercises - Page 781: 41


$$ f_x(1,2)= -164$$

Work Step by Step

Since $ f(x,y)=3x^2y+4x^3y^2-7xy^5$, then we have $$ f_x=6xy+12x^2y^2-7y^5.$$ Hence, we get $$ f_x(1,2)=6(2)+12(4)-7(2^5)=-164$$
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